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/ The Cantor Set
Iterated Function System
Discovered 1874 / 1883
Dimension log 2 / log 3 ≈ 0.631
The Cantor Set
C
0
=
[
0
,
1
]
,
C
n
+
1
=
C
n
3
∪
(
C
n
3
+
2
3
)
C_0 = [0,1], \qquad C_{n+1} = \frac{C_n}{3} \cup \left(\frac{C_n}{3} + \frac{2}{3}\right)
C
0
=
[
0
,
1
]
,
C
n
+
1
=
3
C
n
∪
(
3
C
n
+
3
2
)
★
Cool Fact
The Cantor set has zero total length, yet it's uncountable — the same cardinality as the interval it's cut from. A set can be simultaneously “almost nothing” by one measure and “just as big as everything” by another.
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The Sierpinski Triangle